Answer:
The answer is
5.66 %
Explanation:
The percentage error of the density can be found by using the formula
[tex]Percentage \: \: error(\%) = \frac{error}{actual \: \: number} \times 100 \\ [/tex]
From the question
actual density = 1.59 g/cm³
error = 1.68 - 1.59 = 0.09
The percentage error is
[tex]P(\%) = \frac{0.09}{1.59} \times 100\% \\ = 5.66037735...[/tex]
We have the final answer as
5.66 %
Hope this helps you
