Karissa17
Karissa17 Karissa17
  • 24-04-2018
  • Mathematics
contestada

Find the probability of rolling a twelve first and then a three when a pair of dice is rolled twice?

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Аноним Аноним
  • 24-04-2018
Total number of possible outcomes = 36

Total number of outcomes with a sum of 12 = 1
{6,6)

Total number of outcomes with a sum of 3 = 2
{1,2}{2,1}

P(12 first, then 3) = (1/36)(2/36) = 1/648

Answer: The probability is 1/648
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konrad509
konrad509 konrad509
  • 17-07-2018

[tex] |\Omega|=6^2\cdot6^2=1296\\
|A|=1\cdot2=2\\\\
P(A)=\dfrac{2}{1296}=\dfrac{1}{648}\approx0.2\% [/tex]

Answer Link

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