billybobbrown
billybobbrown billybobbrown
  • 24-04-2018
  • Mathematics
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MI NEED MORE HELPLL with a problem

MI NEED MORE HELPLL with a problem class=

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imagreatbminus
imagreatbminus imagreatbminus
  • 24-04-2018
You can just plug in the answers for x and solve, so for A, if you plug in 10 for x, 10 times 2 is twenty, minus one is 19, which is not less then 10, so A can't be the answer regardless of the other two. So just keep plugging in numbers until you get a set that all has answers less than 10.
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mimii72
mimii72 mimii72
  • 24-04-2018
hI bABy aNsWeR mE NOWWWWWWW!!!!!!!!!!!!!!! <3
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