criste71p5lz00
criste71p5lz00
23-04-2018
Mathematics
contestada
Help me plz with this
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Аноним
Аноним
23-04-2018
[tex] \dfrac{x + 1}{x^3 - x} = \dfrac{x + 1}{x(x^2 -1) } = \dfrac{x + 1}{x(x - 1)(x + 1)} = \dfrac{1}{x(x-1)} = \dfrac{1}{x^2 - x} [/tex]
Answer: J
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