briannaml briannaml
  • 22-04-2018
  • Mathematics
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PLZ HELP ASAP LAST SIMMILAR TRIANGLES

PLZ HELP ASAP LAST SIMMILAR TRIANGLES class=

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cerverusdante
cerverusdante cerverusdante
  • 23-04-2018
Remember that in similar triangles the corresponding sides are proportional. Knowing this, we can establish a proportion between sides AD and AB, and  between sides ED and CB.
[tex] \frac{AD}{AB} = \frac{ED}{CB} [/tex]
[tex]\frac{AD}{2} = \frac{1}{x}[/tex]
Notice that AD=2+1=3, so:
[tex] \frac{3}{2} = \frac{1}{x} [/tex]
Solving for [tex]x[/tex]:
[tex]x= \frac{2}{3} [/tex]

We can conclude that the value of [tex]x[/tex] is [tex] \frac{2}{3} [/tex]
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