We can solve the problem by applying Ohm's law: [tex]V=IR[/tex] where V is the voltage in the circuit I is the current in the circuit R is the resistance
The element of the dryer of the problem has a resistance of [tex]R=7.0 \Omega[/tex], and the voltage applied to the circuit is [tex]V=240 V[/tex], so we can use the previous relationship to calculate the current flowing in the element of the dryer: [tex]I= \frac{V}{R}= \frac{240 V}{7 \Omega}=34.3 A [/tex]
