Respuesta :

[tex]\bf \textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2\sqrt{3}}{4}\qquad \begin{cases} s=length~of\\ \qquad a~side\\ -------\\ s=6 \end{cases}\implies A=\cfrac{6^2\sqrt{3}}{4}\implies A=\cfrac{36\sqrt{3}}{4} \\\\\\ A=9\sqrt{3}[/tex]
lewser321

Answer:

27[tex]\sqrt{3}[/tex]

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