SarahBrainly2017 SarahBrainly2017

24-03-2018
Chemistry

contestada

Using the balanced equation below, how many grams of lead would be required to make 119g of water?

Pb + PbO2 + 2H2SO4 -> 2PbSO4 + 2H2O

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lamya548 lamya548

24-03-2018

The answer to your question is

Not counting the led would be

(119 g H2O) / (18.01532 g H2O/mol) x (1 mol Pb / 2 mol H2O) x (207.21 g Pb/mol) = 684 g Pb

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