First we write both functions: f (x) = x ^ 2 - 3x + 3 g (x) = ((x-1) / (4)) We now make the composition of functions: f (g (x)) = ((x-1) / (4)) ^ 2 - 3 (((x-1) / (4))) + 3 We now evaluate for x = 5: f (g (5)) = ((5-1) / (4)) ^ 2 - 3 (((5-1) / (4))) + 3 f (g (5)) = 1 Answer: f (g (5)) = 1
