desiremarie1999 desiremarie1999

23-01-2018
Physics

contestada

What s the value of work done on an object when a 10-newton force moves it 30meters and the angle between the force and the displacement at 25 degrees

Respuesta :

HenryLCH HenryLCH

25-01-2018

Horizontal component = cos(25)* 10 = 9.06 N
work done = 9.06*30 = 271.9 J

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