anwitakasar31 anwitakasar31

23-12-2017
Mathematics

contestada

In the right △ABC with m∠C = 90°, m∠A = 75°, and AB = 12 cm. Find the area of △ABC.

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tynollette tynollette

23-12-2017

sinA=BC/AB =>BC=sin75*12
cosA=AC/AB =>AC=cos75*12
the area is (1/2)AC*AB=(1/2)sin75*12*cos75*12=18

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ayaannowaz ayaannowaz

14-12-2020

Answer:

18

Step-by-step explanation:

pog pog pogu

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