If the velocity is constant then the acceleration of the object is zero. [tex]a=0 (m/s^2)[/tex] Thus when we apply the equation [tex]\Delta X=vt+(at^2/2) [/tex] It remains [tex]\Delta X =vt [/tex] or equivalent [tex]t=(\Delta X/v) =7500/278 =26.98 (seconds)[/tex]
