jahnays16
jahnays16
21-09-2017
Mathematics
contestada
.help me thanks much
Respuesta :
choixongdong
choixongdong
21-09-2017
(16x^1/6y^-2)^3/2 / (x^-1/6y^6)^3/2
=(4^2)^3/2 (x^1/6)^3/2 (y^-2)^3/2 / (x^-1/6)^3/2(y^6)^3/2
= 4^3 x^1/4 y^-3 / x^-1/4 y ^9
= 64 x^(1/4 +1/4) y^(-3-9)
= 64 x^1/2 y^-12
= 64 x^1/2 / y^12
answer is D.64 x^1/2 / y^12
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