The Molarity
concentration is expressed in units of moles / L. So let us first determine the
number of moles of CH3OH, and then divide that amount by the total volume of
0.230 L of solution.
To determine the number of moles of CH3OH, divide the weight
in grams of CH3OH by the molecular weight of CH3OH: (MW of CH3OH = 32
g / mol)
number of moles = 16.8 g / (32 g / mol)
number of moles = 0.525
mol CH3OH
Then we calculate for molarity:
Molarity = 0.525 mol
CH3OH / .230 L
Molarity = 2.2826 mol /
L
Molarity = 2.28 M
