Find the value of [tex]sin( \frac{5 \pi }{3} )[/tex]
Rewrite as [tex]sin( \frac{6 \pi - \pi }{3} )[/tex]
[tex]sin( \frac{6}{3} \pi - \frac{ \pi }{3} ) [/tex]
[tex]sin(2 \pi - \frac{ \pi }{3} )[/tex]
since sin(π/3) = √3/2
and sin(π-α) = -sinα
α is sin(π/3) of course
[tex]-sin( \frac{ \pi }{3} )[/tex]
[tex]- \frac{ \sqrt{3} }{2} [/tex]
