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  • 25-06-2017
  • Mathematics
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If sec theta = 2,find 4 cos theta-root 3 sin theta/tan theta

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Аноним Аноним
  • 29-06-2017
cos theta = 1  /sec theta  so  cos theta = 1/2

and 4 cos theta = 4 * 1/2 = 2

sin theta  = sqrt ( 1 - cos^2 theta) = sqrt 1 - 1/4) =   sqrt (3/4) =   sqrt3/2

root 3 sin theta  =  3/2

tan theta = sin theta / cos theta =  sqrt3 / 2 / 1/2  = 2*sqrt3/ 2 = sqrt3

so the answer is    2 -  3/2  / sqrt3  =  1/2 / sqrt3  =  sqrt3 / 6
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