Given two exponential functions:
[tex]g(x)=3(2^x)[/tex] and [tex]h(x)=2^{x+1}[/tex]
[tex]k(x) = (g-h)(x)[/tex] is given by
[tex]k(x)=g(x)-h(x) \\ \\ =3(2^x)-2^{x+1}=3(2^x)-2(2^{x}) \\ \\ =2^x(3-2)=2^x[/tex]
Therefore, the option that gives the formula for k(x) = (g - h)(x) is option A.
[tex]k(x)=2^x[/tex]
