kenyambenton
kenyambenton
24-04-2014
Mathematics
contestada
Find the value of x.
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Аноним
Аноним
30-04-2014
[tex]\frac{y}{11}=\frac{5}{y}\\\\y^2=55\\\\\\x^2=5^2+y^2\\\\x^2=25+55\\\\x^2=80\\\\x=\sqrt{80}\\\\x=\sqrt{16\cdot5}\\\\x=4\sqrt5[/tex]
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