the two legs will have the same measure so we can use pytagoras and solve
[tex]H=\sqrt[]{2}\times l[/tex]
replace the value of H
[tex]10=\sqrt[]{2}\times l[/tex]
and solve for l
[tex]\begin{gathered} l=\frac{10}{\sqrt[]{2}} \\ \\ l=5\sqrt[]{2}\approx7.07 \end{gathered}[/tex]
the length of one leg is five roof of two or 7.07
