We will have the following:
[tex]\begin{cases}I=r^2m \\ \\ L=I\omega \\ \\ \omega=v/r\end{cases}[/tex]
So:
We will find the data we can with the given information:
[tex]\omega_1=\frac{0.3m/s}{0.2m}\Rightarrow\omega=\frac{1.5}{s}[/tex]
Also:
[tex]I\omega_1=I\omega_2\Rightarrow\omega_1=\omega_2[/tex]
So:
[tex]\frac{1.5}{s}=\frac{v}{0.03m}\Rightarrow v=0.045m/s[/tex]
So, the velocity at the bottom of the funnel is 0.045m/s.
