NorelleE585810 NorelleE585810
  • 25-10-2022
  • Mathematics
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How do I simplify my answer of 42i^2+32i+6 when the original problem was (2-6i)(3-7i)

Respuesta :

JerzeeC364912 JerzeeC364912
  • 25-10-2022

Given problem is

[tex](2-6i)(3-7i)[/tex]

Now,

[tex]\begin{gathered} (2-6i)(3-7i)=42i^2-14i-18i+6 \\ =42i^2-32i+6 \end{gathered}[/tex]

We know that

[tex]i^2=-1[/tex]

Using this face,

[tex]\begin{gathered} 42i^2-32i+6=-42-32i+6 \\ =-32i-36 \end{gathered}[/tex]

Hence, the simplified form is

[tex]-32i-36[/tex]

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