Answer:
[tex]g'(y)=3y^2-4y-8[/tex]
Step-by-step explanation:
start by foiling out the given function
[tex]g(y)=(y-4)(2y+y^2)\\=2y^2+y^3-8y-4y^2\\=y^3-2y^2-8y[/tex]
next, use the power rule to find the derivative
power rule: To use the power rule, multiply the variable's exponent n, by its coefficient a, then subtract 1 from the exponent. If there's no coefficient (the coefficient is 1), then the exponent will become the new coefficient.
[tex]g'(y)=3y^2-4y-8[/tex]
