keeping in mind that the circle has a radius of 1.6 ft.
[tex]\textit{area of a circle}\\\\ A=\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=1.6 \end{cases}\implies A=\pi (1.6)^2\implies A=2.56\pi \implies A\approx 8.04~ft^2 \\\\[-0.35em] ~\dotfill\\\\ \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=1.6 \end{cases}\implies C=2\pi (1.6)\implies C=3.2\pi \implies C\approx 10.05~ft[/tex]
