The volume of NaOH needed to neutralize 40. ml of 0.15 m Hcl acid is 12 mL.
Volume of base needed
The volume of base needed to neutralize 40. ml of 0.15 m Hcl acid is calculated as follows;
C1V1 = C2V2
V1 = (C2V2)/C1
V1 = (40 x 0.15)/(0.5)
V1 = 12 mL
Thus, the volume of NaOH needed to neutralize 40. ml of 0.15 m Hcl acid is 12 mL.
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