Answer:
(y + 10)(3y - 1)
Step-by-step explanation:
3y² + 29y - 10
consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term.
product = 3 × - 10 = - 30 and sum = + 29
the factors are + 30 and - 1
use these factors to split the y- term
3y² + 30y - y - 10 ( factor first/second and third/fourth terms )
= 3y(y + 10) - 1 (y + 10) ← factor out (y + 10) from each term
= (y + 10)(3y - 1)
3y² + 29y - 10 = (y + 10)(3y - 1) ← in factored form
