Answer:
[tex]\huge\boxed{\sf v_o=3.1\ m/s}[/tex]
Explanation:
Given Data:
Acceleration due to gravity = g = -9.8 m/s²
Maximum Height = h = 0.490 m
At h, [tex]v_f[/tex] = 0
Required:
[tex]v_o=?[/tex]
Formula:
[tex]2gh=v_f^2-v_o^2[/tex]
Solution:
Put the givens
[tex]2 (-9.8) (0.490) = (0)\² - v_o^2\\\\-9.604=-v_o^2\\\\9.604=v_o^2\\\\Take \ sqrt\ on \ both \ sides\\\\\sqrt{9.604}=v_o^2\\\\3.1 \ m/s=v_o\\\\v_o=3.1\ m/s\\\\\rule[225]{225}{2}[/tex]
