Answer:
187.407g
Explanation:
Moles of solute = Molarity × Liters of solution
Multiply 0.60 M by 1.50L:
0.60 mol/ 1L×1.50L=0.9 mol
To obtain the mass of solute, we will need to the molar mass of BaCl2, which is 208.23g/mol:
Finally, multiply the number of moles by208.23g /mol
0.9mol×208.23g/1mol =187.407g
Boom, you have a mass of:
187.407g
