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SBC is an isosceles triangle with main vertex S.
→ Let D be the symmetric of B with respect to C and A the symmetric of C with respect to B.
1) Compare AB and CD
2) Compare the angles SBA et SCD.
3) Deduce that the triangles SBA and SCD are congruent.
4) What is the nature of the SAD triangle?
Help me if u help me u get points I’m poor help me I don’t have much time :(

Respuesta :

Answer + Step-by-step explanation:

1) D be the symmetric of B with respect to C then CD = BC

A the symmetric of C with respect to B then AB = BC

We obtain :

CD = BC

AB = BC

Then AB = CD

2) m∠SBA = 180 - SBC = 180 - SCB = m∠SCD

3) we have :

BA = CD

BS = CS

m∠SBA = m∠SCD

Then

the triangles SBA and SCD are congruent

4)

the triangles SBA and SCD are congruent Then SA = SD

Therefore SAD is an isosceles triangle.

beccamckinney1977

Answer:

its SAD

Step-by-step explanation:

I did the test

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