sleepinglion2233 sleepinglion2233
  • 21-04-2022
  • Chemistry
contestada

The Ksp of scandium fluoride, ScF3, is 5.81×10−24. Calculate the molar solubility ,s, of this compound.

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pstnonsonjoku
pstnonsonjoku pstnonsonjoku
  • 28-04-2022

The Ksp shows the extent of solubility of a substance in another. The solubility of the compound is 1.2 * 10^-7 M.

What is solubility?

The term solubility shows the extent to which a substance dissolve in solution. The solubility of a substance is often typified by the Ksp of the substance.

Now;

ScF3(s) ⇄Sc^+(aq) + 3F^-

Ksp = [Sc^+] [F^-]^3

Ksp = x (3x)^3

Ksp = 27x^4

x = 4√5.81×10^−24/27

x = 1.2 * 10^-7 M

Learn more about Ksp: https://brainly.com/question/27132799

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