Answer:
4.7 Liters of NO2
Explanation:
mole weight of HNO3 (from periodic table) = ~~ 63 gm/mole
12 grams of this is 12/63 = .19047 mole
From the equation, you should be able to see that 3 moles of NO2 produces 2 moles of HNO3
so you need 3/2 * moles HNO3 = .2857 moles of NO2 needed
PV = nR T n = moles R = .082057 L-atm/(k-mole) 25 C = 298.15 K
1.6 (V) = .2857 (.082057)(298.15)
solve for V = 4.37 liters of NO2
