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23-01-2017
Mathematics

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Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four, solve for f(g(x)) when x = 5.

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Аноним Аноним

23-01-2017

g(x) = the quantity of x minus one, over four

g(x) = (x-1)/4

g(5) = (5-1)/4

g(5) = 4/4

g(5) = 1

f(x) = x2 − 3x + 3

f(g(5)) =1^2 − 3(1) + 3

f(g(5)) = 1 - 3 + 3

f(g(5)) = 1

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