Respuesta :
The osmotic pressure of the solution is 25.48atm
Data;
- Mass = 69.5g
- Molar mass = 162.20g/mol
- Volume = 2.35L
- Temperature = 35.0^oC
Osmotic Pressure
The osmotic pressure of the solution is calculated as
[tex]\pi = iMRT[/tex]
- i = Vant Hoff Factor
- M = molarity
- R = gas constant
- T = Temperature
The Vant hoff factor of the factor = 4
Let's calculate the molarity of the solution;
[tex]M = \frac{number of moles}{volume}[/tex]
Number of moles = mass / molar mass
[tex]n = \frac{mass}{molar mass} \\[/tex]
substitute the values into the formula and solve for it
[tex]n = \frac{69.5}{162.20} \\n = 0.428 moles[/tex]
The molarity of the solution is calculated as
[tex]M = \frac{number of moles}{volume} \\M = \frac{0.428}{2.35} = 0.182 mol/L[/tex]
The osmotic pressure of the solution is calculated as
[tex]\pi = iMRT\\\pi = 4 * 0.182 * 35\\\pi = 25.48 atm[/tex]
The osmotic pressure of the solution is 25.48atm
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