Answer:
See below
Step-by-step explanation:
[tex] \frac{ {x}^{4} }{ {x}^{ - 3} {y}^{0} } = \frac{ {x}^{4 + 3} }{ {y}^{0} } = \frac{ {x}^{7} }{1} = {x}^{7} \\ \\ 2 {x}^{ - 3} = \frac{2}{ {x}^{3} } \\ \\ {( {x}^{ - 3} )}^{8} = {x}^{ - \times 8} = {x}^{ - 24} = \frac{1}{ {x}^{24} } [/tex]
