keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the line above
[tex](\stackrel{x_1}{-1}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{(-2)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-1)}}}\implies \cfrac{8+2}{3+1}\implies \cfrac{10}{4}\implies \cfrac{5}{2}~\hfill \stackrel{\textit{\large nope}}{\cfrac{5}{2}\ne 3}[/tex]
