0928316623
0928316623 0928316623
  • 23-12-2021
  • Mathematics
contestada

Find an equation of the plane through (-1,4,-3) and perpendicular to the line x-2=t , y+3=t , z=-t​

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sqdancefan
sqdancefan sqdancefan
  • 23-12-2021

Answer:

  x + y -z = 6

Step-by-step explanation:

The equation of the line can be rewritten as ...

  (x, y, z) = (2, -3, 0) +t(1, 1, -1)

The direction vector of the line tells you the coefficients of the variables in the equation of the plane. The constant in that plane equation will be the value required to make it pass through the given point.

  x + y - z = (-1) +(4) -(-3)

  x + y - z = 6 . . . . equation of the plane

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