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the input nums is supposed to be an array of unique integers ranging from 1 ro nums.length (inclusive). However, there is a mistake: one of the numbers in the array is replicated, which means another number is missing. find and return he sum of the duplicate number and the missing number

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fichoh

The program which returns the sum of the duplicate and missing number is written in python 3 thus ;

def dup(nums):

#initialize a function which takes In a list of values as argument.

nums.sort()

#sort the values in ascending order

for i in range(1, len(nums)):

#iterate through the list

if nums[i] == nums[i-1]:

#Check for repeated values

return nums[i] + nums[i]-1

#return the sum of the repeated values - 1

nums = [4,3,3,1]

print(dup(nums))

A sample run of the program is attached.

Learn more : https://brainly.com/question/25574075

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