[tex] 3.35 \times 10 ^{ - 11} [/tex]
Explanation:
proof:
[tex]m1= 5 kg \\ \\ m2 = 10 kg[/tex]
[tex]distance \: \: between \: \: objects = 10 cm \\ \\ force \: \: of \: \: attraction = ? \\ \\ F= g m1 \times \frac{m2}{ {d}^{2} } \\ \\ =6.7 \times {10}^{ - 11} \times 5 \times \frac{10}{ {10}^{2} } \\ \\ = 67 \times {10}^{ - 11} \times 5 \times \frac{10}{100 \times 10} \\ \\ = 67 \times \frac{ {10}^{ - 11} }{20} \\ \\ =6.7 \times \frac{ {10}^{ - 11} }{2} \\ \\ = 3.35 \times 1 {0}^{ - 11} [/tex]
hope it helps
