Step-by-step explanation:
The given equations are
x2+y3=xy9
⟹xy2y+3x=xy9
⟹3x+2y=9 ........(i)
x4+y9=xy21
⟹xy4y+9x=xy21
⟹9x+4y=21 ........(ii)
Now (i)×3⟶9x+6y=27 .....(iii)
Subtracting (iii) from (ii),
−2y=−6⇒y=3.
Putting y=3 in (i),
3x+2×3=9⟹x=1.∴(x,y)=(1,3)
