DriParrondahepalma
DriParrondahepalma DriParrondahepalma
  • 23-12-2016
  • Chemistry
contestada

How many grams of NH3 can be produced from 2.93mol of N2 and excess H2?

Respuesta :

johnkellock
johnkellock johnkellock
  • 24-12-2016
1 mol of N2 is 28 gms, thus, 2.93mol is 84 gms.

According to the equation-

N (2 + 3H (2) =  2NH(3) 

28gms (1mol) of N2 produces 34gms of NH3

so, 84gms of N2 will produce:

28gms of N2----->34gms of NH3
84gms of N2-----> 28/84 = 34 / x

x= (34*84) / 28

Answer: 102gms
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