Answer:
C and D.
Step-by-step explanation:
We want to solve the equation:
[tex](x-1)^2 = 50[/tex]
We can take the square root of both sides. Since we are taking an even root, we need plus/minus:
[tex]\displaystyle (x-1) = \pm\sqrt{50}[/tex]
Note that:
[tex]\sqrt{50} = \sqrt{2\cdot 5^2} = 5\sqrt{2}[/tex]
Hence:
[tex]\displaystyle (x - 1) = \pm5\sqrt{2}[/tex]
And by adding one to both sides:
[tex]\displaystyle x = 1 \pm 5\sqrt{2}[/tex]
In conclusion, our answers are both C and D.
