Respuesta :

mhanifa

Answer:

  • A = 1, B = 9, C = 8

Step-by-step explanation:

Given:

  • AA + BB + CC = ABC

Rewrite it as:

  • 11A + 11B + 11C = 100A + 10B + C
  • 89A = B + 10C

Since all A, B, C are integers from 0 to 9, A can be 1 only, then we have:

  • B + 10C = 89

or

  • CB = 89

It gives us:

  • C = 8, B = 9

The equation is:

  • 11 + 99 + 88 = 198

Answer:

ABC=198

Step-by-step explanation:

If you do 11+99+88 then you get 198 which is true to the problem that you have.

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