pointegirl01
pointegirl01 pointegirl01
  • 23-07-2021
  • Mathematics
contestada

Please help!!!!

CE is tangent to this circle, CD is a radius and ECB=48 what is BAC​

Please helpCE is tangent to this circle CD is a radius and ECB48 what is BAC class=

Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 28-07-2021

Answer:

48degrees

Step-by-step explanation:

From the circle geometry shown, traingle BDC is an isosceles triangle which shows means that their base angels are the same. Hence;

<B = <C

<CBD + <BCD + <D = 180

<BCD + <BCD + <D =180

2<BCD + <BDC = 180

Get <BCD;

<BCD+ <ECB = 90

<BCD + 48 = 90

<BCD = 90 - 48

<BCD = 42degrees

Get <BDC

2<BCD + <BDC = 180

2(42)+ <BDC = 180

84 + <BDC = 180

<BDC = 180 - 84

<BDC = 96

Since angle at the centre is twice that at the circumference, then;

<BAC = 1/2(<BDC )

<BAC = 96/2

<BAC = 48degrees

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