ranjushrestha1122
ranjushrestha1122 ranjushrestha1122
  • 22-07-2021
  • Mathematics
contestada

( 1,-2), gradient = -3​

Respuesta :

mwabamwaba2004
mwabamwaba2004 mwabamwaba2004
  • 22-07-2021

Answer:

if you are required to find the equation of a straight line use the formula y-y1= m (x-x1)

y+2=-3(x-1)

y+2=-3x+3

y= -3x+3-2

y -3x+1

hope this helps

Answer Link
loconte loconte
  • 22-07-2021

Answer:

y = -3x + 1

Step-by-step explanation:

(y -(-2)) = -3(x-1)

y+ 2 = -3x+ 3

y = -3x + 1

Answer Link

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me ajudem por favor na numero 1 e 2