hailinhndc hailinhndc

22-07-2021
Mathematics

contestada

[tex]\sqrt{4+\sqrt{4+\sqrt{4+...+\sqrt{4}[/tex]

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Аноним Аноним

31-07-2021

Answer:

y=0.5+sqrt(17)

Step-by-step explanation:

Let y=sqrt{4+sqrt{4+...+sqrt(4)}

y=sqrt(4+y). (Since it's an infinite series)

y^2=4+y, y=0.5-sqrt(17) or 0.5+sqrt(17). We will omit the negative since root values are positive.

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