Answer:
Step-by-step explanation:
First get everything on the same side of the equals sign and set the quadratic equal to 0:
[tex]x^2+x-5=0[/tex] where a = 1, b = 1, c = -5:
[tex]x=\frac{-1+-\sqrt{1^2-4(1)(-5)} }{2(1)}[/tex] which simplifies down a bit to
[tex]x=\frac{-1+-\sqrt{21} }{2}[/tex] and your 2 solutions are
[tex]x=\frac{-1+\sqrt{21} }{2}[/tex] and [tex]x=\frac{-1-\sqrt{21} }{2}[/tex]
