Answer:
Let's define A as the area given by the integral:
[tex]\int\limits^1_{-1} {3x^4} \, dx[/tex]
Which is the area between the curve y = 3*x^4 and the x-axis between x = -1 and x = 1
To find the volume of a revolution around the x-axis, we need to multiply the area by 2*pi (a complete revolution)
where pi = 3.14
First, let's solve the integral:
[tex]\int\limits^1_{-1} {3x^4} \, dx = \frac{3}{5}(1^5 - (-1)^5) = \frac{3*2}{5} = \frac{6}{5}[/tex]
Then the volume of the solid is just:
V = (6/5)*2*3.14 = 7.536
