Answer:
3(3x - 10)(9x² + 30x + 100)
Step-by-step explanation:
Given
81x³ - 3000 ← factor out 3 from each term
= 3(27x³ - 1000 )← a difference of cubes which factors in general as
a³ - b³ = (a - b)(a² + ab + b²) , then
27x³ - 1000
= (3x)³ - 10³
= (3x - 10)((3x)² + (3x)(10) + 10²)
= (3x - 10)(9x² + 30x + 100)
Then
81x³ - 3000 = 3(3x - 10)(9x² + 30x + 100) ← in factored form
