Answer:
For a general quadratic equation like:
y = a*x^2 + b*x + c
a is the leading coefficient.
And we define the vertex of this as (h, k)
Where h is:
h = -b/(2*a)
and k is the y-value given when we use x = h.
Now, in this case we have:
f(x) = 5*x^2
We can see that the leading coefficient is 5, then a = 5.
To find the value of h we use:
h = -b/(2*a)
there is no lineal term, thus b = 0, then:
h = -0/(2*5) = -0/10 = 0
and k is given by
f(h) = f(0) = 5*0^2 = 0
then k = 0.
Concluding:
a = 5
h = 0
k = 0
