Answer:
x≤21/10
Step-by-step explanation:
[tex] \frac{1}{5} - 2x \geqslant - 4 \\ - 2x \geqslant - 4 - \frac{1}{5 } \\ 2x \leqslant 4 + \frac{1}{5} \\ 2x \leqslant \frac{21}{5} \\ x \leqslant \frac{21}{10} [/tex]
