The above reaction is a Single displacement reaction , in which lead (Pb) being more reactive displaces Copper (Cu) from its compound [tex](\mathrm{CuCl_2})[/tex] and forms Lead Chloride [tex](\mathrm{PbCl_2})[/tex].
[tex] \boxed{\mathrm{Pb + CuCl_2 \rightarrow PbCl_2 + Cu}}[/tex]
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[tex]\mathrm{ \#TeeNForeveR} \: ☃[/tex]
